Question

the digit at the ten's place of a two digit number is four times the digit at ones place if the sum of this number and the number formed by reversing the digit is 55 find the number

Answer 1

Hey,

Let the digit at the ones place be x

Then the digit at the tens place will be = 3x

Therefore the number is 10(3x) +x 

= 30x+x 

= 31x

By reversing the digits we get 10(x)+3x 

= 10x+3x 

= 13x

Their sum = 88

⇒31x + 13x = 88

⇒ 44x = 88

⇒ x = 88/44

∴ x = 2
Then the digits are x, 3x = 2 and 3(2)

= 2 and 6

The number = 31x 

= 31(2)

= 62

∴ The number is 62...

HOPE IT HELPS:-))