The digit at The ten's place of A Two digit Number is four time that in the unit's place. if the digit Are Reversed The new number will be 54 less than The original Number. Find The Original Number
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hey mate
here's the solution
here's the solution
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Step-by-step explanation:
Let the Number at the units place be x.Tenth place = 4x
Then,
➳ Number = 10(x) + 4x
➳ Number = 10x + 4x
➳ Number = 14x
➳ Reversing Number = 10(4x) + x
➳ Reversing Number = 40x + x
➳ Reversing Number = 41x
According to Question now,
➳ 14x - 41x = -54
➳ -27x = -54
➳ x = -54/-27
➳ x = 54/27
➳ x = 2
Units place = x = 2
Tenths place = 4x = 4(2) = 8
Therefore,
Number = 10(8) + 2 = 80 + 2 = 82
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