Question

The digit at the ten's place of a two digit number is three times the digit at the unit's place. If the sum of this number and the number formed by reversing it's digits is 88, find the number.

Answer 1

The number is 62.
6 (ten's place) is three times 2 (one's place)

Reversing 62, we get 26.
Adding 26 to 62, we get 88