The digit at the tens place of 2 digit no is three times the digit at ones place if the sum of this no and the no formed by reversing its digit is 88 find the no
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Suggestion: You should try to it by yourself, after that post here. Just use your logic, that's it. No offense.
Let the unit digit of the original two digit number be x, where x is not equal to 0
Then, the digit at the tens place of the original number is = 3x
then, ATP, we can right that:
The original number :
10(3x) + x
= 30x + x
= 31x
The reversed number :
10x + 3x
= 13x
Therefore, we can write that:
31x + 13x = 88
=》44x = 88
=》x = 88/44
=》x = 2
Therefore the unit digit of the original number = x = 2
the digit in the tens place of the original number = 3x = 6
ANSWER: THE ORIGINAL NUMBER IS 62
I HOPE IT HELPS
:)
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