Question

the digit at the tens place of a 2 digit number is three times the digit at the ones place. If the sum of this number and the number formed by reversing its digits is 88.Find the number

Answer 1

let x = the 10's digit
let y = the units
then
10x+y = the number
" the digit at the tens place of a two digit number is three times the digit at ones place."
x = 3y
"The sum of this number and the number formed by reversing its digit is 88,"
(10x + y) + (10y + x) = 88
10x + x + 10y + y = 88
11x + 11y = 88
simplify, divide by 11
x + y = 8
3y+ y = 8
4y=8
y=2

x = 3.2 = 6
The number is = 10.x + y
                         = 10.6 + 2
                          = 62

Hope this helps! :))