Question

)the digit at the tens place of a two digit number is four times that in the units place if the digit are reserved the new number will be 54 less than the original number find the original number check your solution ​

Answer 1

Answer:

82

Step-by-step explanation:

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Answer 2

${\green{\underline{\textsf{\textbf{Answer : }}}}}$

The number is 82.

${\green{\underline{\textsf{\textbf{Explaination : }}}}}$

Let's assume

➩ The numbers are x(ten's digit) and y (ones digit)

Number formed :

➩ 10x + y

Reversing the digits :

➩ 10y + x

As it is told that x is 4 times y

So, x = 4y ...... (i)

According to the question,

$\sf : \implies \: (10x + y) - (10y + x) = 54 \\ \sf : \implies \: 10x + y - 10y - x = 54 \\ \sf : \implies \: 9x - 9y = 54 \\ \sf : \implies \:9( x - y) = 54 \\ \sf : \implies \: x - y = \frac{54}{9} \\ \sf : \implies \: x - y = 6 \\ { \underbrace{ \textbf{ \textsf{ From ..(i)}}}} \\ \sf : \implies \: 4y - y = 6 \\ \sf : \implies \: 3y = 6 \\ \sf : \implies \: y = \frac{6}{3} \\ \sf : \implies \: y = 2$

After solving we get :

➩ y = 2

And also,

x = 4y

x = 4*2

x = 8

Hence,

The number is :

➩ 10x + y

➩ (10*8) + (2)

➩ 80 + 2

➩ 82 ans.