Question

The digit at the tens place of a two digit number is three times the digit at the ones place. If the sum of the no. and the no. formed by reversing its digits is 88. find the orginal two digit number

Answer 1

Ans.

Let, the digits are x and y.
Then the number is (10x + y).
When the digits are reversed, the number becomes
(10y + x).

Then,
x = 3y .....(i)

(10x + y) + (10y + x) = 88
or, 11x + 11y = 88
or x + y = 8 .....(ii)

We put x = 3y in (ii). Then
3y + y = 8
i.e., 4y = 8
i.e., y = 2

From (i), we get
x = 6

Therefore, the number is 62.

***I HOPE THAT THIS HELPS YOU***

Answer 2

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