Question

the digit at the tens place of a two digit number is three times the digit at the onecs place if the sum of this number and the number fromed by revesing it's digits is 88 find the number.

Answer 1

heya bro!!!!

gud evening..!!

here iz ur anzzz....

Let the digit at the ones place be x

Then the digit at the tens place will be = 3x

Therefore, the number is 10(3x) + x

= 30x + x

= 31x

By reversing the digits, we got 10(x) + 3x

= 10x + 3x

= 13x

Their sum = 88

=> 31x + 13x = 88

=> 44x = 88

=> x = 88/44

Therefore, x = 2

Then the digits are x, 3x = 2 and 3(2)

= 2 and 6

The number = 31x

= 31(2)

= 62

Therefore, the number is 62.


hope it hlps u!!

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