the digit at the tens place of a two-digit number is twice the digit at the units place. if the sum of this number and the number formed by reversing the digits is 66, find the number
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Let x be the tens digit and y be the units digit.
Actual number = 10x + y
Reverse number = 10y + x
x = 2y (tens digit is twice the units digit)
10x + y + 10y + x = 66
11x + 11y = 66
x + y = 6
2y + y = 6
3y = 6
y = 2
x = 2y
= 4
The number is 42.
Actual number = 10x + y
Reverse number = 10y + x
x = 2y (tens digit is twice the units digit)
10x + y + 10y + x = 66
11x + 11y = 66
x + y = 6
2y + y = 6
3y = 6
y = 2
x = 2y
= 4
The number is 42.
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