Question

the digit at the tens place of two digit number is 4 times that in the unit's place of the digits are reversed the new number will be 54 less than the original number find the number

Answer 1

let x be the tens place no and y be the unit place no .

so real no =(10x+y)

when reverse no will be (10y+x).

a/q,

x=4y.................(i)

10x+y=10y+x-54

or 9x-9y =54

or x-y=6

or 4y-y=6                     (from equ (i))

or 3y=6

therefore y=3

in equ (i),

x=4y

 =4*3=12

therefore no=123 ans

Answer 2

Answer

let x be the tens place no and y be the unit place no .

so real no =(10x+y)

when reverse no will be (10y+x).

a/q,

x=4y.................(i)

10x+y=10y+x-54

or 9x-9y =54

or x-y=6

or 4y-y=6                     (from equ (i))

or 3y=6

therefore y=3

in equ (i),

x=4y

 =4*3=12

therefore no=123 ans