Question

the digit at the tens place of two digit number is three times the digit at the unit place if the digit are reversed the new number will be 36 less than the original number find the number​

Answer 1

Answer:

let the digit in the one's place be x

Then, the digit in the tens place = 3x

The no. formed is = 10 x 3x + x= 31x

If the digits are reversed, the new number formed is 10 X x + 3x = 13x

13x = 31x - 36

x = 2

The original no. = 31 X 2 = 62

Answer 2

Answer:

The Original Number is 62.

Step-by-step explanation:

Given :

The digit in the tens place of two digit number is = three times that in the unit place.

When the digits are reversed, the new number will be = 36 less than the original number.

To find :

The original number

Solution :

Original Number -

Consider the -

• Units Place as y
• Tens Place as 10(3y)

Number Formed = 10(3y) + y

⇒ 30y + y

⇒ 31y ..... [Original Number]

$\rule{300}{1.5}$

Number with Reversed Digits -

Consider the -

• Units Place = 3y
• Tens Place = 10(y)

Number Formed = 10(y) + 3y

⇒ 10y + 3y

⇒ 13y ..... [Number with Reversed Digits]

$\rule{300}{1.5}$

As given in the Question -

When the digits are reversed, the new number will be = 36 less than the original number.

⇒ 13y = 31y - 36

⇒ 13y - 31y = - 36

⇒ - 18y = - 36

⇒ 18y = 36 .... (Negative signs to be cancelled)

⇒ y = 36/18

⇒ y = 2

$\rule{300}{1.5}$

As we got the value of y, find the original number by placing the y's value.

⇒ 31y

⇒ 31(2)

⇒ 62

Original number = 62

$\therefore$ The Original Number is 62.