Question

The digit in the hundreds place of a three-digit number is 3 times the digit in the units place; the digit in its tens place is twice the digit in the units place. If the sum of all the three digit is 12,find the number

Answer 1

Answer:

let the digit in the unit place is x

so digit in hundred place is 3x

and the digit in tens place is 2x

according to question,

x+3x+2x=12

=> 6x=12

=> x=12/6

=> x=2

so the digit in unit place is 2

digit in hundred place is 3×2=6 and digit in tens place is 2×2=4

so the number is 642

Answer 2

Answer:

The number is 642

Step-by-step explanation:

Let,

• Units place = x

• The digit in the hundreds place of a three-digit number is 3 times the digit in the units place

• Hundreds place = 3x

•The digit in its tens place is twice the digit in the units place.

• Tens place = 2x

• The sum of all the three digit is 12 (Given)

★ According to the Question :

Units place = x

Hundreds place = 3x

Tens place = 2x

⇒ x + 3x + 2x = 12

⇒ 6x = 12

⇒ x = 12/6

⇒ x = 2

Units place = 2

Hundreds place = 3x

⇒3 (2)

⇒ 6

Hundreds place = 6

Tens place = 2x

⇒ 2 (2)

⇒ 4

Tens place = 4

Therefore, the number is 642.