Question

The digit in the ten’s place of a two-digit number is three more than the digit in the unit’s place. If the digit at unit’s place be y, then the number is ​

Answer 1

Given :

• A two-digit number is three more than the digit in the unit’s place.

• The digit at unit’s place be y.

To find :

• The number =?

Step-by-step explanation :

A two-digit number is three more than the digit in the unit’s place. [Given]

The digit at unit’s place is y. [GIVEN]

As it is Given that,

The digit at unit’s place is y.

∴ Digit in ten’s place is (y + 3)

According to the question :

Two digit number = 10 × digit in ten’s place + digit in unit’s place.

Substituting the values, we get,

= 10 × (y + 3) + y

= 10 × y + 10 × 3 + y

= 10y + 30 + y

= 11y + 30

Therefore, The number is 11y +30.

Answer 2

GIVEN :

=> A two - digit number is 3 more than the digit

in the unit's place.

=> The digit at units place by 'y'

TO FIND :

=> The number = ?

Step-by-step explaination :

=> (GIVEN), A two - digit number is 3 more than the digit in the unit's place.

=> (GIVEN), The digit at unit place be 'y'

So, here digit in tens place is (y+3)

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As per the question :

Now, after Substituting the value ,

$= 10 \times (y + 3) + y$

$= 10 \times y + 10 \times 3 + y$

$= 10y + 30 + y$

$= 11y + 30$

Hence, The number = (11y + 30)

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