Question

the digit in the tens place of a two digit number is 3 times that in the unit if the digits are reserved the new number will be 36 less than the original number find the original number

Answer 1

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according to question let, the unit digit = x then the tens digit = 3x because according to question tens digit is 3 times of unit digit. now the number = 10(3x) + x = 31x put it eq'n 1 now , reversing the original number 10(3x) + x = 10x + 3x . 10x + 3x = 31x -36 . 36 = 31x -13x . next 36 = 18x . now x = 2 . put the value of x in eq'n 1 , 31(2)= 62 the original number obtained is 62

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Answer 2

${\orange{\underline{\textsf{\textbf{Answer : }}}}}$

The number is 62.

${\purple{\underline{\textsf{\textbf{Explaination : }}}}}$

Let's assume

➩ The numbers are x(ten's digit) and y (ones digit)

Number formed :

➩ 10x + y

Reversing the digits :

➩ 10y + x

As it is told that x is 3 times y

So, x = 3y ...... (i)

According to the question,

$\sf : \implies \: (10x + y) - (10y + x) = 36 \\ \sf : \implies \: 10x + y - 10y - x = 36 \\ \sf : \implies \: 9x - 9y = 36 \\ \sf : \implies \:9( x - y) = 36 \\ \sf : \implies \: x - y = \frac{36}{9} \\ \sf : \implies \: x - y = 36 \\ { \underbrace{ \textbf{ \textsf{ From ..(i)}}}} \\ \sf : \implies \: 3y - y = 36 \\ \sf : \implies \: 2y = 36 \\ \sf : \implies \: y = \frac{4}{2} \\ \sf : \implies \: y = 2$

After solving we get :

➩ y = 2

And also,

x = 3y

x = 3*2

x = 6

Hence,

The number is :

➩ 10x + y

➩ (10*6) + (2)

➩ 60 + 2

➩ 62 ans.