the digit in the tens place of a two digit number is 3 times that in the units place if the digits are reversed the new number will be 36 less than the original number find the original number check your solution
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as per question , the required number must satisfy the following ;
DIGIT IN TENS PLACE OF TWO DIGIT NUMBER SHOULD BE THREE TIMES GREATER THAN IN THE UNITS PLACE .
IF THE DIGIT IS REVERSE THE NEW NUMBER SHOULD BE 36 LESS THAN THE ORIGINAL NUMBER
SO, let the number be XY where Y = 3X
: when Y = 1
number formed will be 31 and when the digits are reversed , number formed is 13 but the difference will not be equal to 36 , so 31 is not the required number.
: when Y = 2
number formed will be 62 and when the digits are reversed , number formed is 26 , as you can observe their difference is 36 , HENCE 62 IS THE REQUIRED NUMBER.
DIGIT IN TENS PLACE OF TWO DIGIT NUMBER SHOULD BE THREE TIMES GREATER THAN IN THE UNITS PLACE .
IF THE DIGIT IS REVERSE THE NEW NUMBER SHOULD BE 36 LESS THAN THE ORIGINAL NUMBER
SO, let the number be XY where Y = 3X
: when Y = 1
number formed will be 31 and when the digits are reversed , number formed is 13 but the difference will not be equal to 36 , so 31 is not the required number.
: when Y = 2
number formed will be 62 and when the digits are reversed , number formed is 26 , as you can observe their difference is 36 , HENCE 62 IS THE REQUIRED NUMBER.
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