The digit in the tens place of a two digit number is three times that in the units place. If the digits are reversed, the new number will be 36 less than the original number. Find the original number. Check your solution.
PLSSSSS ANSWER ASAP. I HAVE EXAM ON MONDAY
Answers
Answered by
2
according to question let, the unit digit = x then the tens digit = 3x because according to question tens digit is 3 times of unit digit. now the number = 10(3x) + x = 31x put it eq'n 1 now , reversing the original number 10(3x) + x = 10x + 3x . 10x + 3x = 31x -36 . 36 = 31x -13x . next 36 = 18x . now x = 2 . put the value of x in eq'n 1 , 31(2)= 62 the original number obtained is 62
mathwiz86:
thnx a lot
and tens place no. be 3x
therefore the original no be = 10×3x+x=30x+x
on reversing the no.
the new no. be 10×x+3x=10x+3x
ATQ
30x+x-(10x+3x)=36
31x-10x-3x+36
18x=36
x=2
so, the original no. is 10×3×2+2=62
Answered by
3
Answer:
let units digit be x,
ATQ,
tens digit = 3x
the number= 10(3x) + x = 30x + x = 31x
number when digits reversed= 10x + 3x = 13x
13x = 31x - 36
13x - 31x = -36
-18x = -36
x = 2
the original number = 10*3*2 + 2 = 62
Similar questions
Math,
5 months ago
English,
5 months ago
CBSE BOARD X,
11 months ago
Physics,
11 months ago
Psychology,
1 year ago