Question

The digit in the tens place of a two digit number is three times that in the units place. If the digits are reversed, the new number will be 36 less than the original number. Find the original number. Check your solution.



PLSSSSS ANSWER ASAP. I HAVE EXAM ON MONDAY​

Answer 1

according to question let, the unit digit = x then the tens digit = 3x because according to question tens digit is 3 times of unit digit. now the number = 10(3x) + x = 31x put it eq'n 1 now , reversing the original number 10(3x) + x = 10x + 3x . 10x + 3x = 31x -36 . 36 = 31x -13x . next 36 = 18x . now x = 2 . put the value of x in eq'n 1 , 31(2)= 62 the original number obtained is 62

Answer 2

Answer:

let units digit be x,

ATQ,

tens digit = 3x

the number= 10(3x) + x = 30x + x = 31x

number when digits reversed= 10x + 3x = 13x

13x = 31x - 36

13x - 31x = -36

-18x = -36

x = 2

the original number = 10*3*2 + 2 = 62