Question

The digit in the tens place of a two-digit number is three times that in the units place. If the digits are
reversed, the new number will be 36 less than the original number. Find the original number. Check your
solution
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Answer 1

• Let one's digit number be M and ten's digit number be 3M

• Original number = 3 × 10M + M = 30M + M

• Reversed number = 10M + 3M

» The digit in the tens place of a two-digit number is three times that in the units place. If the digits are reversed, the new number will be 36 less than the original number.

A.T.Q.

=> 30M + M - (10M + 3M) = 36

=> 31M - 13M = 36

=> 18M = 36

=> M = 2

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From above calculations we have M = 2

So,

One's digit = M = 2

And ten's digit = 3M = 3(2) = 6

So,

Original number = 30M + M

=> 30(2) + 2

=> 60 + 2

=> 62

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$\textbf{Original number = 62}$

__________ [ ANSWER ]

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Answer 2

$\huge\textbf{Answer:-}$

Let x be the number

=30x + x - (10x + 3x) = 36

=31x - 13x = 36

=18x = 36

=x = 2

x = 2

= 3x = 3(2) = 6

= 30x + x

=30(2) + 2

=60 + 2

=62

Answer is 62