The digit in the tens place of a two digit number is three more than the digit in the unit place. Let the digit at the unit place be b. Then the number is (a) 11 b + 30 (b) 10b + 30 (c) 11b + 3 (d) 10 b + 3
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Answer:
Answer = (a) 11b+30
Step-by-step explanation:
Say the 2 digit number is ab
ab can be expanded as ab=10*a +b
As per condition given, a=b+3
So ab=10(b+3)+b
=10b+30+b
=11b+30
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