The digit in the tens place of a two digit number is three times the digits at ones place. if the sum of this number and the number formed by reversing its digits is 88, find the number.
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unit digit = x
tens digit = 3x
two digit number = 10(3x)+x = 31x
reverse of this number = 10(x) +3x = 13x
sum = 88
31x + 13x = 88
44x =88
x = 2
given number = 31x = 31×2 =62
tens digit = 3x
two digit number = 10(3x)+x = 31x
reverse of this number = 10(x) +3x = 13x
sum = 88
31x + 13x = 88
44x =88
x = 2
given number = 31x = 31×2 =62
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