Question

the digit in the tens place of a two digit number is three times that in the unit place if the digits are reversed the new digit number will be 36 less than the original number find the original number check your solution

Answer 1

Answer:

62

Step-by-step explanation:

let one digit be = x

therefore second digit = 3x

number = 10(3x)+x

equation = 10(3x) + x = 10x + 3x + 36

                =>30x + x = 13x + 36

                =>31x  - 13x = 36

               =>18x = 36

               =>x = 36/18

              =>x = 2

Checking your answer;

putting in the value of x we get

3x ,x

3 multiplied 2, 2

62

and 6 is three times 2

hope it helps you please let me know if any problem

             

Answer 2

Answer:

62

Step-by-step explanation:

Let the one's digit be y and tens digit be x,

Number = 10x + y

Then,x=3y⋯(i)

Reversed number = 10y + x

A.t.Q :- (10x+y)−(10y+x)=36 Put x = 3y in eq. (i)

⇒9x−9y=36

⇒x−y=4⋯(ii)

⇒3y−y=4

∴2y=4 x=3y ∴x=6

y=2

∴ Number = 62