the digit in the tens place of a two digit number is thrice three times the digit in the units place if the digits are reversed the new number will be 36 less than the original number find the number
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according to question let, the unit digit = x then the tens digit = 3x because according to question tens digit is 3 times of unit digit. now the number = 10(3x) + x = 31x put it eq'n 1 now , reversing the original number 10(3x) + x = 10x + 3x . 10x + 3x = 31x -36 . 36 = 31x -13x . next 36 = 18x . now x = 2 . put the value of x in eq'n 1 , 31(2)= 62 the original number obtained is 62
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