Question

The digit in the tens place of two digit number is three times that in the units place.if the digits are reversed,the new number will be 36 less than the original number.find the original number.check your solution

Answer 1

Hi ,

Let the unit place digit = x

ten's place digit = 3x

original number = 10 × 3x + x

= 30x + x

= 31x ----( 1 )

if the digits are reversed the new number

= 10x + 3x

= 13x ------( 2 )

according to the problem given ,

if the digits are reversed , the new number

will be 36 less than the original number

31x - 13x = 36 [ from ( 1 ) and ( 2 ) ]

18x = 36

x = 36 / 18

x = 2

Therefore ,

The original number = 31x

= 31 × 2

= 64

I hope this helps you.

:)

Answer 2

Answer:

Let the Number at the units place be x.

Tenth place = 3x

Then,

➳ Number = 10(x) + 3x

➳ Number = 10x + 3x

➳ Number = 13x

➳ Reversing Number = 10(3x) + x

➳ Reversing Number = 30x + x

➳ Reversing Number = 31x

According to Question now,

➳ 13x - 31x = -36

➳ -18 = -36

➳ x = -36/-18

➳ x = 36/18

➳ x = 2

Units place = x = 2

Tenths place = 3x = 3(2) = 6

Therefore,

Number = 10(6) + 2 = 60 + 2 = 62