The digit of a two digit number differ by 2. If the digit are interchanged of the resulting number is added to the original number, we get 154. Find the number.
Answers
The digit of a two digit number differs by 2.
Let the tens digit number be x and ones digit number be y.
Tens digit number - Ones digit number = 2
If the digit is interchanged of the resulting number is added to the original number, we get 154.
Assumed tens digit number is x and ones digit number is y.
Therefore, Original number = 10(tens digit number) + (ones digit number)
⇒ 10(x) + y
Interchanged number = 10(ones digit number) + (tens digit number)
⇒ 10(y) + x
Interchanged number + Original number = 154
Take 11 as common on both sides
11 throughout cancel
Now, Substitute the value of x from (eq 1)
Take 2 as common on both sides
Substitute value of y in (eq 1)
We have to find the original number. From the above calculations, we have tens digit number (x) = 8 and ones digit number (y) = 6
Therefore,
Original number = 10(8) + 6 = 86
Given
A word problem
- In which a two digit no differ by 2
- when we interchanged the digit the new + original no be 154
To find
the no
Solution
Let the no in one's place be X and tens be y
Then
Y-x=2______(1)
According to the question
Original no = 10y+X
Interchanged no= 10x+y
Now adding original no and interchanged no
10y+X+10x+y=154
=>11y+11x=154
=>11(y+x)=154
=>y+X=14________(2)
From equation (1) and (2)
Y-x=2
y+X=14
_____
=>2y=16
y=8
putting the value of y in equation (1)
y-x=2
=>8-x=2
X=6