Question

the digit of two digit number are in ratio 2 ratio 3 and the number obtained by interchanging the digit is greater than the original number by 27 what is the original numberd​

Answer 1

Answer:

69

Step-by-step explanation:

Let the two digits be 2x and 3x since the digits are in the ratio 2:3.

The number is 2x (10) + 3x which is 23x. [The tens digit is considered to be 2x.]

When the original number's digits are interchanged, that is the number becomes 3x (10) + 2x = 32x, the difference between the original number and the derived number is 27.

Therefore 32x - 23x = 27

                 9x = 27

                 x = 3

When substituting x=3 in 23x, we get 69.

[The number 53 is 5 (10) + 3. This is a general form for expressing 2 digit numbers.

We took the original number's tens digit as 2x because in the question it is given that the interchanged number is greater than the original number.]

Answer 2

Answer:

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Step-by-step explanation:

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