Question

the digit of two digit number differ by 6.the sum of the numbers and the number formed by reversing its digt is 132.find the number?​

Answer 1

ANSWER:

120

Step-by-step explanation:

let the digits be X and y

and number be 10x + y

reversed number = 10y + x

x - y = 6 ....(1)

and also,

10x + y + 10y + X = 132

11x + 11y = 132

11(x + y) = 132

x + y = 132/11

x + y = 12 ....(2)

(1) + (2)

x - y + x + y = 6 + 12

2x = 18

x = 18/2

x = 9

putting the value of x on (1)

x - y = 6

9 - y = 6

-y = 6 - 9

-y = -3

y = 3

SO,

number = 10x + y

= 10(9) + 3

= 90 × 3

93

so,

the number = 93

Answer 2

Answer:

x - y = +6 equation 1

   0r

x - y = -6

no. = 10x +y

reversed no. = 10y +x

sum = 10x + y +10y +x

11x + 11y = 132

11(X+y) =132

x+ y = 132/11

x + y = 12 equation 2

adding equ. 1 and 2 we get

2x = 18

x = 9

as x - y = 6

 so

9 - y = 6

y = 9-6 =3

no. = 10x + y

= 10*9 + 3

= 90  + 3 = 93.

it can also be 39

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Step-by-step explanation: