the digits at the tens place is 5 less than twice the digit at units place. The sum of the original number and the number obtained bye interchanging the digits is 176
Answers
let the unit digit be x
∴the tens digit is 2x-5
∴the nos is 10*[2x-5] +x =20x-50+x =[21x -50] ..............................[1]
⇒now by interchanging the digits we get
⇒tens digit is x and unit digit is [2x-5]
∴the new nos becomes 10*x+[2x-5] =10x+[2x-5] =[10x +2x-5] =[12x -52].......[2]
ATP
⇒[21x -50]+[12x -5] =176
⇒21x+12x -50 -5 =176
⇒33x-55 =176
⇒33x=176+55
⇒33x=231
⇒x=231/33 =7 ==========units place nos
∴the tens digit is 2x-5 =2*7-5 = 14-5 =9
∴the nos is 97 ans
proof 97 +79 =176
Answer:the number thought is 97
Step-by-step explanation:
According to the 1st condition
x+5= 2y
Rearranging:x-2y= -5
According to the 2nd condition
10x+y+10y+x= 176
i.e x+y= 16
Solving equ 1 and 2
x - 2y = -5
x + 2y = -16
____________
0 -3y = -21
y = - 21
____ = 7
- 3
Substituting y = 7 in equ 2
x + y = 16
x + 7 = 16
x = 16 - 7
x = 9
.
. . x = 9 ; y =7
The nis thought : 10x + y
10(9) + 7
90 + 7
= 97