Question

The digits at the tens place of a two digits number is three times the digits at the ones place . If the sum of this number and the number formed by reversing its digit is 88 . find the number . The Answer is 62. Any body can solve it. It is totally 100 points​

Answer 1

Answer:

hope this helps u :-)

Step-by-step explanation:

Let the digit at the ones place be x

Then the digit at the tens place will be = 3x

Therefore the number is 10(3x) +x  

= 30x+x

= 31x

By reversing the digits we get 10(x)+3x 

= 10x+3x

= 13x

Their sum = 88

⇒31x + 13x = 88

⇒ 44x = 88

⇒ x = 88/44

∴ x = 2

Then the digits are x, 3x = 2 and 3(2)

= 2 and 6

The number = 31x 

= 31(2)

= 62 ans

∴ The number is 62.

Answer 2

Answer:

hello mate...

Step-by-step explanation:

.

refer to the attachment ...

thanky