Question

the digits in the tens place of a two -digit number is three times the digit in the units place.If the digits are reversed the new number will be 36 less than the original number.Find the number

Answer 1

let the ones digit no. be x
let the tens digit no. be y
no so formed = 10y + x
A. T. Q
x = 3y
if the digits are reversed then the number so formed is 10x+y
so,
10y + x - ( 10x + y) = 36
10y + x - 10x - y = 36
9y - 9x = 36
y - x = 4
substituting the value of x ( x = 3y)

Answer 2

Step-by-step explanation:

Let the Number at the units place be x.Tenth place = 3x

Then,

➳ Number = 10(x) + 3x

➳ Number = 10x + 3x

➳ Number = 13x

➳ Reversing Number = 10(3x) + x

➳ Reversing Number = 30x + x

➳ Reversing Number = 31x

According to Question now,

➳ 13x - 31x = -36

➳ -18 = -36

➳ x = -36/-18

➳ x = 36/18

➳ x = 2

Units place = x = 2

Tenths place = 3x = 3(2) = 6

Therefore,

Number = 10(6) + 2 = 60 + 2 = 62