Question

The digits in the tens place of a two digit number is three times that in the units place.if the digits are reversed the new number is 36 less than the original number.what is the original number?

Answer 1

Let us assume, x is the tenth place digit and y is the unit place digit of the two-digit number.

Therefore, the two digit number = 10x + y and reversed number = 10y + x

Given:

x = 3y -----------------1

Also given:

10y + x = 10x + y - 36

9x - 9y = 36
x - y = 4 ----------------2

Substitute the value of x from equation 1 in equation 2

3y - y = 4
2y = 4
y = 2

Therefore, x = 3y = 3 * 2 = 6

Therefore, the original two-digit number = 10x + y = 10 * 6 + 2 = 62

Answer 2

Step-by-step explanation:

Let the Number at the units place be x.Tenth place = 3x

Then,

➳ Number = 10(x) + 3x

➳ Number = 10x + 3x

➳ Number = 13x

➳ Reversing Number = 10(3x) + x

➳ Reversing Number = 30x + x

➳ Reversing Number = 31x

According to Question now,

➳ 13x - 31x = -36

➳ -18 = -36

➳ x = -36/-18

➳ x = 36/18

➳ x = 2

Units place = x = 2

Tenths place = 3x = 3(2) = 6

Therefore,

Number = 10(6) + 2 = 60 + 2 = 62