Question

The digits of a 2-digit number differ by 5. If the digits are interchanged and the resulting number is added to the original number, we get 99. Find the original number.

Answer 1

Here is the solution.

Give me BRAINLIST or Thank You.

Answer 2

Heyaa user!!!!
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Good morning!!!
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Here's your solution :-

Let the digit in the ones place be y and the digit in the ten's place be x........

Then, the number becomes 10x+y......

Here, two cases are possible :-

Case 1....

When x>y

Then, x-y=5. ..........(i)

Also, 10y+x+10x+y=99

=>11x+11y=99

=>x+y=9. ..............(i)

Equating both equations, we get :-

x+y-x+y=9-5

=>2y=4

=>y=2

So, x =9-2=7

Hence the number becomes 72.......
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Case 2.......

When y>x,

Then, y-x=5. .............(i)

Also,

x+y=9. ...............(from eq. (ii) of the above case)

Now, equating we get :-

x+y+y-x=9+5

=>2y=14

=>y=7

Now, x=7-5=2

So, the equation becomes 27.......

Hope this helps!!!!