Question

The digits of a 2-digit number differ by 5. If the digits are interchanged and the resulting number is added to the original number, we get99. Find the original number.

Plz explain each step i am not getting it plz write why the step is so

Answer 1

Let the unit digit = x

Tens digit = 10x

When digits are interchanged ,

Tens digit = 10x

Unit digit = x+2

= (10 +x+2)+10x+20+x= 99

11x + 2+11x+20

22x+22=99

22x=99-22

x = 77/22

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