The digits of a three digit positive number are in A.P. and the sum of digits is 15. On subtracting 594 from the number, the digits are interchanged. Find the number
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35
let the digits be : a-d,a, a+d
: the no. is -- 100(a-d) +10a+ a+d ---------(1)
it is given that sum of digits is 15
therefore we get
3a = 15
a=5
now subtract 594 from (1)
and equate with
a-d + 10a+ 100(a+d)
: the no. is -- 100(a-d) +10a+ a+d ---------(1)
it is given that sum of digits is 15
therefore we get
3a = 15
a=5
now subtract 594 from (1)
and equate with
a-d + 10a+ 100(a+d)
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