the digits of a three digit positive number are in AP and their sum is 15 the number obtained by reversing the digit is 594 less than the original number find the number
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852 is the correct answer
let the numbers are :- a,b,c
then in AP b = a+b /2
so a+b =2b
and acc. to que a+b+c =15
so b +2b =15
b =5
now from above photo that i attatch 0,10 or10,0can not be
the value of a &c because it itself become 3digit but there is b also for making 3digit no
now (1,9) (2,8)(3,7)(4,6)(5,5) are also not satisfy the given condition because the no. came after reverse of original digit is 594 less but by (1,9) (2,8)(3,7)(4,6)(5,5) these no. it didn't so we start checking from (6,4)(7,3)(8,2),(9,1)
and finally 8,2satisfy the question's condition
and hence a,b,c
i.e. 852 is ans
let the numbers are :- a,b,c
then in AP b = a+b /2
so a+b =2b
and acc. to que a+b+c =15
so b +2b =15
b =5
now from above photo that i attatch 0,10 or10,0can not be
the value of a &c because it itself become 3digit but there is b also for making 3digit no
now (1,9) (2,8)(3,7)(4,6)(5,5) are also not satisfy the given condition because the no. came after reverse of original digit is 594 less but by (1,9) (2,8)(3,7)(4,6)(5,5) these no. it didn't so we start checking from (6,4)(7,3)(8,2),(9,1)
and finally 8,2satisfy the question's condition
and hence a,b,c
i.e. 852 is ans
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Aishkhokher:
how bro
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