Math, asked by nasirquasim, 10 months ago

The digits of a two digit number are in the ratio
of 2 : 3 and the number obtained by interchanging
the digits is greater than the original number by
27. What is the original number?​

Answers

Answered by navneet1208
3

Step-by-step explanation:

check for the attachment I hope it's clear

Attachments:
Answered by vikramsingh91755
1

Answer:

Let the ratio be x.

first digit = 2x

second digit= 3x

((So we can write a two digit no. as.

for ex. 25= 2× 10 + 5))

original no. = 10 × 2x + 3x

no. obtained by interchanging the digit = 10× 3x + 2x

so acc. to the condition

10× 3x + 2x = 10× 2x +3x + 27

30x + 2x = 20x + 3x +27

32x - 23x= 27

9x = 27

x= 27/9

x= 3

so our original no. is 2×3 =6 and 3×3= 9

And. 69

Similar questions