Math, asked by luk3004, 5 months ago

The digits of a two-digit number differ by 3.If the digits are interchanged, and the resulting number is added to the original number,we get 121.Find the original number.

With suitable explanation

Answers

Answered by Anonymous
0

Answer:

74, 47 (two answers possible)

Step-by-step explanation:

Let the tenths place digit be x and once place be y.

Original number=10(x)+1(y)

=10x+y

Interchanging digits of number=10(y)+1(x)

= 10y+x

According to question,

10y+x+10x+y=121

11x+11y=121

11(x+y)=121

x+y=11----------1

Case 1

If x >y

Then x-y=3--------------2

Adding 1 & 2

x+y+x-y=11+3

2x=14

x=7

7-y=3(from 2)

y=7-3

y=4

Thus, number is 74.

Case 2

If y>x

Then y-x=3--------------3

Adding equation 1&3

x+y+y-x=11+3

2y=14

y=7

7-x=3

x=7-3

x=4

Thus, number is 47

In this type of question, two answers are possible.

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