The digits of a two-digit number differ by 3.If the digits are interchanged, and the resulting number is added to the original number,we get 121.Find the original number.
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Answer:
74, 47 (two answers possible)
Step-by-step explanation:
Let the tenths place digit be x and once place be y.
Original number=10(x)+1(y)
=10x+y
Interchanging digits of number=10(y)+1(x)
= 10y+x
According to question,
10y+x+10x+y=121
11x+11y=121
11(x+y)=121
x+y=11----------1
Case 1
If x >y
Then x-y=3--------------2
Adding 1 & 2
x+y+x-y=11+3
2x=14
x=7
7-y=3(from 2)
y=7-3
y=4
Thus, number is 74.
Case 2
If y>x
Then y-x=3--------------3
Adding equation 1&3
x+y+y-x=11+3
2y=14
y=7
7-x=3
x=7-3
x=4
Thus, number is 47
In this type of question, two answers are possible.
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