Question

The digits of a two digit number differ by 3.If the digits are interchanged and the resulting number is added to the original number we get 143 .What can be the original number?

Answer 1

You can find the answer here

Answer 2

Let the unit digit ( largest digit ) be x
and tens digit ( smallest digit ) be y

Original number :- 10y + x

Interchanged number :- 10x + y


• Digit differ by 3

x - y = 3 ..... ( i )

10y + x + 10x + y = 143

11y + 11x = 143

( dividing by 11 )

y + x = 13 ..... ( ii )


Add ( i ) & ( ii )

x - y + y + x = 3 + 13

2x = 16

x = 8


Putting in ( ii )

x + y = 13

y = 13 - 8

y = 5


Original number :- 10y + x

10 × 5 + 8

50 + 8

58

So, Required number is 58