The digits of a two- digit number differ by 3. If the digits are interchanged, and
the resulting number is added to the original number, we get 143, What is the
original number?
Answers
ASSUMPTIONS :
- The two digit number is a natural number.
- the digits of the number are x and y
- the original number is 10x + y.
- x is greater than y.
GIVEN :
digits of a 2 digit number differ by 3.
∴ x - y = 3........(ii)
addition of the new no. and original number = 143.
SOLUTION :
The new no. formed by interchanging the digits = 10y + x.
new no. + original no. = 143
(10y + x) + (10x + y) = 143
10y + y + 10x + x = 143
11x + 11y = 143
11(x + y) = 143
x + y = 143/11
x + y = 13 ........(i)
Adding equations (i) and (ii) :
(x + x) + (y - y) = (3 + 13)
2x = 16
x = 16/2
x = 8
Replacing the value of x in eqn (i) :
8 - y = 3
y = 5
Since the original number is 10x + y
= (10 × 8) + 5
= 85
The original number is 85. (Ans
Solve:-
According to question ❓:-
Take , for example , a 2 digit number , say, 56.
Take , for example , a 2 digit number , say, 56. It can be written as 56 = (10 × 5) + 6.
~If the digits in 56 are interchanged , We get 65 , which can be written as (10×6) + 5.
• Let us take the two digit number such that the digit in the unit place is b.
• The digit in the tens place is different from b by 3.
• Let us take it as b + 3.
• So the two digit number is 10 (b+3) + b
= 10b + 30 + b
= 11b + 30
With interchange the digits , the resulting two number will be
= 10b + (b+3) = 11b + 3
If we add these two two digit numbers , their sum is
(11b + 30) + (11b + 3) = 11b + 11b + 30 + 3
= 22b + 33
It is given that the sum is 143.
Therefore , 22b + 33 = 143
• 22b = 143 - 33
• 22b = 110
• b = 110/22
• b = 5
Now,
Unit place = b
The value of b is 5 .
So, The unit place is 5.
Unit place = 5
Tens place = b + 3
So , We have to sum the both numbers.
Value of b = 5
So ,
b + 3
= 5 + 3
= 8
hence,
the number is 85.
Answer is verified.
Answering check ✅ => On interchange of digits the number we get is 58.
The sum of 85 and 58 is 143 are given.
Hope it helps you ❤️