Question

The digits of a two digit number differ by 3. If the digits are interchanged and the

resulting number is added to the original number we get 143. What can be the original

number.

Answer 1

Hey,
Let the two digit number be 10(x+y),
x-y = 3 (first equation)

10(y+x)+10(x+y)=143
10y+10x+10x+10y=143
20x + 20y = 143 (second equation)

Now, in the first equation,
x=3+y

Substitute X's value in equation second,

20(3+y)+20y = 143
60+20y+20y = 143
60+40y = 143
40y = 83
y = 2.1.

And, x=3+2.1
x=5.1.

Original number = 10(x+y)
=10(5.1+2.1)
=72.

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