Question

The digits of a two-digit number differ by 3. If the digits are interchanged, and the resulting number is added to the original number, we get 143. What can be the original number
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Answer 1

Let one’s digit of a two-digit number be x

Given that the difference between both the digits is 3,

Then ten’s digit = x + 3

Hence, the number = x + 10 (x + 3)

= x + 10x + 30

= 11x + 30

By interchanging the digits, we get,

One’s digit of a new number = x + 3 and

Ten’s digit of a new number = x

Hence,

Number = x + 3 + 10x = 11x + 3

According to the condition,

11x + 30 + 11x + 3 = 143

22x + 33 = 143

22x = 143 – 33

We get,

22x = 110

x = 110 / 22

x = 5

Therefore, original number = 11x + 30

= 11 × 5 + 30

= 55 + 30

We get,

= 85

Answer 2

Answer:

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Step-by-step explanation:

Let one’s digit of a two-digit number be x

Given that the difference between both the digits is 3,

Then ten’s digit = x + 3

Hence, the number = x + 10 (x + 3)

= x + 10x + 30

= 11x + 30

By interchanging the digits, we get,

One’s digit of a new number = x + 3 and

Ten’s digit of a new number = x

Hence,

Number = x + 3 + 10x = 11x + 3

According to the condition,

11x + 30 + 11x + 3 = 143

22x + 33 = 143

22x = 143 – 33

We get,

22x = 110

x = 110 / 22

x = 5

Therefore, original number = 11x + 30

= 11 × 5 + 30

= 55 + 30

We get,

= 85