the digits of a two digit number differ by 3.If the digits r interchanged & the resulting number is added to the original number ,we get 143. What can be the original number?
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Hi there !!
Here's your answer
Given,
the digits of a two digit number differ by 3
Let the digit in units place be x
Digit in tens place = x + 3
The new number is 10(x+3) + x
= 10x + 30 + x
= 11x + 30 ______(i)
Also,
If the digits are interchanged & the resulting number is added to the original number ,we get 143
By interchanging the digits,
we have,
digit in units place = x + 3
digit in tens place = x
The new number is 10(x) + x + 3
= 10x + x + 3
= 11x + 3 ______(ii)
So
The following balanced equation will be formed
11x + 30 + 11x + 3 = 143
22x + 33 = 143
22x = 143 - 33
22x = 110
x = 110/22
x = 5
So,
Digit in units place = x = 5
Digit in tens place = x + 3 = 5 + 3 = 8
The number is 85 or 58
Here's your answer
Given,
the digits of a two digit number differ by 3
Let the digit in units place be x
Digit in tens place = x + 3
The new number is 10(x+3) + x
= 10x + 30 + x
= 11x + 30 ______(i)
Also,
If the digits are interchanged & the resulting number is added to the original number ,we get 143
By interchanging the digits,
we have,
digit in units place = x + 3
digit in tens place = x
The new number is 10(x) + x + 3
= 10x + x + 3
= 11x + 3 ______(ii)
So
The following balanced equation will be formed
11x + 30 + 11x + 3 = 143
22x + 33 = 143
22x = 143 - 33
22x = 110
x = 110/22
x = 5
So,
Digit in units place = x = 5
Digit in tens place = x + 3 = 5 + 3 = 8
The number is 85 or 58
moon38:
thank u very muchh
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