Question

the digits of a two digit number differ by 5. if the digits are interchanged and resulting number is added to the orignal , we get 99.​

Answer 1

Answer:

Let the digit in ten's. Place be x and the digit in the one's place be y.

∴x−y=5⟶(i)

∴ Two digit number=10x+y

Two digit after reversing the digits=10y+x

According to question ,

∴10x+y+10y+x=99

⇒11x+11y=99

⇒x+y=9⟶(ii)

On adding (i) and (ii),

2x=14

⇒x=7

Putting the value of x in equation (i)

x−y=5

⇒y=2

∴ Number=10x+y

                    =72.

Step-by-step explanation:

Pls mark me as brainlist