the digits of a two digit number differ by 7 if the digits are interchanged and the resulting number is added to the original number we get 121 find the original number
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hi
let the number be xy
tens place = 10x
ones place = y
The digits of a two digit number differ by 7
x - y = 7.....[1]
if the digits are interchanged and the resulting number is added to the original number we get 121
so,
10y + x + 10x +y = 121
11x +11y = 121
now,
x + y = 11.....[2]
now , [1] and [2] since
x - y = 7
x +y = 11
on adding them
2x = 18
x = 9
now y = x - 7
= 9 -7
=2
hence the original number is xy
= 92
hope it helps u
:)
let the number be xy
tens place = 10x
ones place = y
The digits of a two digit number differ by 7
x - y = 7.....[1]
if the digits are interchanged and the resulting number is added to the original number we get 121
so,
10y + x + 10x +y = 121
11x +11y = 121
now,
x + y = 11.....[2]
now , [1] and [2] since
x - y = 7
x +y = 11
on adding them
2x = 18
x = 9
now y = x - 7
= 9 -7
=2
hence the original number is xy
= 92
hope it helps u
:)
Raghav3333:
brainliest pls
Answered by
11
hope this answer will help you
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