Math, asked by Vaishnavi0511, 1 year ago

the digits of a two digit number differ by 7 if the digits are interchanged and the resulting number is added to the original number we get 121 find the original number

Answers

Answered by Raghav3333
32
hi

let the number be xy

tens place = 10x

ones place = y

The digits of a two digit number differ by 7

x - y = 7.....[1]

if the digits are interchanged and the resulting number is added to the original number we get 121

so,

10y + x + 10x +y = 121

11x +11y = 121

now,

x + y = 11.....[2]

now , [1] and [2]  since

x  - y = 7 

x +y = 11

on adding them

2x = 18

x = 9

now y = x - 7

= 9 -7

=2

hence the original number is xy

= 92

hope it helps u

:) 





Raghav3333: brainliest pls
Answered by anand203
11
hope this answer will help you
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