Question

The dilute aqueous solution fluoride is electrolysed the product at the anode and cathode are

Answer 1

Since sodium is a metal , it will deposit on anode because metals are electropositive and fluorine deposit on cathode because it is nonmetal and is electronegative

Answer 2

Answer: Anode: Fluorine

cathode: hydrogen

Explanation: $NaF(aq)\rightarrow Na^+(aq)+F^-(aq)$

$H_2O(l)\rightarrow H^+(aq)+OH^-(aq)$

On passing electricity, both $Na^+$ and $H^+$ move towards the cathode whicle $F^-$ and $OH^-$ move towards anode.

Cathode: As the discharge potential of $H^+$ is lower than that of $Na^+$, therefore  $H^+$ ions is discharged in preference to $Na^+$

$2H^++2e^-\rightarrow H_2$

Thus hydrogen is evolved at cathode.

Anode: As the discharge potential of $F^-$ is lower than that of $OH^-$, therefore  $F^-$ ions is discharged in preference to $OH^-$

$2F^-\rightarrow F_2+2e^-$

Thus fluorine is evolved at anode.