The dimension of a metallic cuboid are 44*42*21.it is melted and recast into sphere find the surface area of the sphere
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61
l * b * h = 4/3 πr³
44*42*21 = 4/3 * 22/7 *r³
(44*42*21*3*7)/4*22 = r³
r = ∛21*21*21
r = 21 cm
surface area of sphere
4πr²
4*22*21*21/7
5544 cm²
44*42*21 = 4/3 * 22/7 *r³
(44*42*21*3*7)/4*22 = r³
r = ∛21*21*21
r = 21 cm
surface area of sphere
4πr²
4*22*21*21/7
5544 cm²
Answered by
20
21 is radius of sphere
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