Question

the dimension of a rectangular box are in the ratio of 2:3:4 and the difference between the cost of covering it which sheet of paper at the gates of rupees 8 and rupees 9.50 per metre square is rupees 1248.Find the dimension of the box.
PLZ ANSWER BRIEFLY.

Answer 1

let dimension of a rectangulqr box be 2x 3x and 4x then
TSA = 2 ( 2x * 3x + 3x * 4x + 4x * 2x )

= 52 x^2


C1 = cost of coveribg at rs.8/unit = 52x^2 * 8
C2 = cost of covering at rs.9.50 = 52x^2 * 9.50

given
C2 - C1 = 1248

52x^2 * 9.50 - 52x^2 * 8 = 1248

taking 52x^2 common

52x^2 ( 9.50 - 8) = 1248

52x^2 * 3/2 = 1248

78x^2 = 1248

x^2 = 1284 / 78

x^2 = 16

x = 4


then.

dimensions are = 8m , 12m , 16 m

hope it helps..

plz. mark as brainly.....

Answer 2

Refer to the attachment above for your solution...
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