Question

The dimensional formula of [∈0E2], where symbols have their usual meaning, is

Answer 1

∈$_{0}$ is permittivity of vacuum with SI unit $A^{2}s^{4}kg^{-1}m^{-3}$

E represents Energy with SI unit $kg.m^{2}.s^{-2}$

[∈$_{0}] = [L^{-3}M^{-1}T^{4}A^{2}]$

$[E_{2}] = [M L^{2} T^{-2}]$

Multiplying both, we have

∈$_{0}E_{2} = A^{2}s^{4}kg^{-1}m^{-3} × kg.m^{2}.s^{-2} = s^{2} A^{2} m^{-1}$

Hence we get the dimensional formula as

[∈$_{0}E_{2}] = [L^{-1}T^{2}A^{2}]$

Answer 2

Explanation:

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