Question

the dimensions of a/b in the relation p=a-t^2/bx: where p= pressure,x=distance and t is the time

Answer 1

Answer:

[M^-1T^-4]

Explanation:

[p]=[a]=[t^2/bx]=[ML^-1T^-2] (Homogeneity principle)

[T^2]/[b][L]=[ML^-1T^-2]

[b]=[T^2]/[ML^-1T^-2][L]

=[M^-1T^-4]