Math, asked by nidhipatni5, 1 month ago

The dimensions of a brick are 24cm X 12 cm X 8cm. how many such bricks will be required to build a wall of 20m length, 48m breadth and 6m high?​

Answers

Answered by sfybhx1378
0

Answer:

1m = 100cm

volume of bricks (V1) = 24×12×8 = 2304cm³

volume of wall (V2) = 2000×4800×600 = 5760000000cm³

No. of bricks = V2/V1 = 5760000000/2304 = 2500,000

Answered by shch4747
0

Answer:

2500000 Bricks

Step-by-step explanation:

To solve this, let's go from dimension to dimension,

In length,

Length of 1 brick=24cm

Length of the wall to be built=20m=2000cm

Number of bricks needed=2000/24

                                          =500/6

                                          =250/3

In breadth,

Breadth of 1 brick=12cm

Breadth of the wall to be built=48m=4800cm

Number of bricks needed=4800/12

                                          =400

In height,

Height of 1 brick=8cm

Height of the wall to be built=6m=600cm

Number of bricks needed=600/8

                                          =75

Now, to calculate the total number of bricks we will multiply these dimensions because the wall is cuboidal in shape and to calculate the volume of a cuboid you multiply the height, the breadth and the length.

So,

Total number of bricks=75 x 400 x 250/3

                                     =25 x 400 x 250

                                     =2500000 Bricks

Hope it helps :)

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