The dimensions of a cubiod are in the ratio of 3:5:7, if its total surface area is 1278 meter square. Find the dimensions of the cubiod?
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Let dimensions be 3x m, 5x m,7x m, where x is the constant of proportionality.
T. S. A=2(lb+bh+lh)=2(3x*5x+5x*7x+7x*3x)=2(15x^2+35x^2+21x^2)=71x^2*2=142x^2
ATP,
142x^2=1278
X=root (1278/142)
x=root (9)
X=3
Therefore, dimensions are -
3x=3*3=9m
5x=5*3=15m
7x=7*3=21m
Hope this help. Mark as brainliest if it's good.
T. S. A=2(lb+bh+lh)=2(3x*5x+5x*7x+7x*3x)=2(15x^2+35x^2+21x^2)=71x^2*2=142x^2
ATP,
142x^2=1278
X=root (1278/142)
x=root (9)
X=3
Therefore, dimensions are -
3x=3*3=9m
5x=5*3=15m
7x=7*3=21m
Hope this help. Mark as brainliest if it's good.
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