Math, asked by Deeptiddls, 10 months ago

The dimensions of a cuboid are in the ratio of 1:2:3 and its total surface area is 88m^2. find the dimensions?

Answers

Answered by Tannnnnnnn
0

Answer:

Step-by-step explanation:

Let the dimensions be x, 2x&3x.

So, S. A of a cuboid=2(lb+bh+hl)

=2(x*2x+2x*3x+3x*x)

2(2x^2+6x^2+3x^2)

=2(11x^2)=22x^2

Now, 22x^2=88(GIVEN)

THEREFORE, x^2=88/22=4

So, x=square root of 4.=2

So, dimensions =

1st=x=2m.

2nd=2x=4m

3rd)=3x=6m.

Thanks

Answered by apaocalipto69
0

Step-by-step explanation:

let us take

1x ,2x,3x

TSA of cuboid is 2*lb +2bh+2hl

so l=1x-a

B=2x-b

c=3x-c

so

88=2*1x*2x+2*2x*3x+2*3x*1x

88=4Xsqare+12Xsqare+6Xsquare

88=22Xsquare

88/22=Xsquare

4=Xsquare

X=square√4

square and root got canceled

so,

X=4

so evaluate X

a,d,c

so 1x=1*4=4

2*4=8

3*4=12,

so dimensions are 4cm ,8cm,12cm.

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